The circular convolution, also known as cyclic convolution, of two aperiodic functions occurs when one of them is convolved in the normal way with a periodic summation of the other function. That situation arises in the context of the Circular Convolution theorem. It occurs naturally in digital signal processing when DTFTs and inverse DTFTs are replaced by DFTs and inverse DFTs. Before going into the details of circular convolution we must know the circular shift, so let us start with circular shift.
The circular shift of a sequence x(n) is defined as follows:
A circular shift may be visualized as follows. Suppose that the values of a sequence x(n), from n = 0 to n = N-1, are marked around a circle as illustrated in Fig. (a) or in an eight-point sequence. A circular shift to the right by 'n 0' corresponds to a rotation of the circle 'n 0' positions in a clockwise direction. An example illustrating the circular shift of a four-point sequence is shown in Fig. (b).
Another way to circularly shift a sequence is to form the periodic sequence with period equal to the length of the given sequence, and then linear shift this periodic sequence by 'n0', and then extract one period of this shifted sequence by multiplying by rectangular window. As shown in figure below:
Circular Convolution
Let h(n) and x(n) be finite-length sequences of length N with N-point DFTs H(k) and X(k), respectively. The sequence that has a DFT equal to the product Y(k) = H(k)X(k) is
The circular convolution of two finite-length sequences h(n) and x(n) is equivalent to one period of the periodic
convolution of the periodic sequences made by the periodic extension of x(n) and h(n), prospectively.
Example
Let us find the four-point circular convolution of the sequences h(n) and x(n)shown in figure:
The four point convolution is given by
To evaluate y(0), we multiply this sequence by x(k) and sum the product from k=0 to k=3. The result is y(0) = 1. Next, to find the value of y(1), we evaluate the sum
The linear convolution of x[n] and h[n] is
Note that the results of circular convolution and linear convolutions are different for same x[n] and h[n]. The short method for finding the circular convolution is to set up a table using the results of linear convolution and evaluate the sum
This is done by listing the values of the sequence y(n+kN) in a table and summing these values for n = 0, 1,2,3. Note that the only sequences that have nonzero values in the interval 0<=n<=3 are y(n) and y(n + 4), and these are the only sequences that need be listed. Thus, we have
Summing the columns for 0<=n<=3, we haveWhich is same as we calculated mathematically.
thanks ....
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